9n/n^2+14=1

Solution for 9n/n^2+14=1 equation:

9n/n^2+14=1

We move all terms to the left:

9n/n^2+14-(1)=0


Domain of the equation: n^2!=0

n^2!=0/

n^2!=√0

n!=0

n∈R


We add all the numbers together, and all the variables

9n/n^2+13=0

We multiply all the terms by the denominator


9n+13*n^2=0

We add all the numbers together, and all the variables

13n^2+9n=0

a = 13; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·13·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*13}=\frac{-18}{26}
=-9/13
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*13}=\frac{0}{26}
=0
$